Question

bool检测;

sizeof(test) = 1 if using VS 2010. Since every C++ data type must be addressable, the "test" bool variable is 8-bits(1 byte).

我的问题是,“测试”在记忆中实际上占了1个。

Is there any implementation skill that can make the bool data type occupy only one bit? If yes, can you give me an example?

bool test1[32](in VS 2010), int test2(in VS 2010)

http://www.ohchr.org。占领同样的记忆?

Answer 1

<代码>试验1的每个要素必须予以处理。这意味着test1 (使用<代码>bool测试1 [32]创建)至少需要32个tes(每个元素1个 by)。

如果你想要将多种生物价值储存在一个单一变量中,使用<代码>std:bitset<>>> 或std:vector<bool>(但认识到后者实际上不是羊毛的载体),则是一种专门设计,可以节省空间。

IIRC, C++11还界定了std:dynamic_bitset。

Answer 2

My question is that does the "test" variable really occupy 1 byte in memory?

Yes, if sizeof(bool)==1 . Basically, the sizeof bool is implementation-defined, which means it could be greater than 1 byte for certain compiler.

bool test1[32](in VS 2010), int test2(in VS 2010)
Does test1 and test2 occupy the same memory?

他们所占领的每一种东西都可以通过使用经营者的规模来知道。这就是经营者的规模。 www.un.org/spanish/ga/president

Answer 3

另一种变数为1比2, 即:

struct {
    int a:1;
    int b:1;
};