Question

我只想接受一定百分比的符号(选择)作为数字的直观变量,就像投入的百分比一样。 E.G, 1000%或100%,或2000年可能,或显示投入为1000或2000年。

我们能否在定期表达的帮助下这样做? 或者可能还有其他一些验证。

请帮助

Answer 1

following

^[+-]?d+(.d+)?%?$

应同男性工作者合作

Answer 2

^[0-9]+%?$

假设至少需要一名数字,只允许肯定数字(或<代码>0)。

如果你也想允许诽谤(你本可以提到这个问题的话),那么尝试

^[0-9]+(?:.[0-9]+)?%?$

这使得任何积极的分类或分类(但并非如<条码>.1或<条码>。当然,接触性标志没有得到支持。

Answer 3

Absolutely. It sounds like you want to sanitize here as well, so "[0-9]{1,}%" or "[0-9]*.?[0-9]{1,}%" to ensure you match fractional percentages.

通常,我可能已经说过,但太少了(fun.org)。 EDIT

rel=“nofollow”>http://www.ual-expressions.info/vis.html

You could do it with a something besides a regex but that would just be a loop that asserts that each character of input is a decimal digit, period, or percent sign, and that they are in the appropriate order.

Hope this helps!

Answer 4

根据这一评论:

it seems to work perfect with patterns like 1000%, 100 but now problems with decimal values like 101.50 or 199.50%

^[-+]?d*.?d+%?$

<>Explanion>:

"
^        # Assert position at the beginning of the string
[-+]     # Match a single character present in the list “-+”
   ?        # Between zero and one times, as many times as possible, giving back as needed (greedy)
[0-9]    # Match a single character in the range between “0” and “9”
   *        # Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
.       # Match the character “.” literally
   ?        # Between zero and one times, as many times as possible, giving back as needed (greedy)
[0-9]    # Match a single character in the range between “0” and “9”
   +        # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
       # Assert position at a word boundary
%        # Match the character “%” literally
   ?        # Between zero and one times, as many times as possible, giving back as needed (greedy)
$        # Assert position at the end of the string (or before the line break at the end of the string, if any)
"

As a side note : You should really have been able to account for the optional part from @ Tim s answer. Take a look at the tutorial proposed by the other answers.

Answer 5

You can try with the digits and % as an optional character.

^d+(.d+)?%?$

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