Question

我想将每个彩色的图像中的物体数计算在内。

例:我想把黄米或绿色大米列入图像。

“entergraph

请让我在一定程度上这样做?

Answer 1

http://www.mathwork.com/products/image/demos.html?file=/products/demos/shipping/images/ipexrice.html 图像处理工具箱。如果你读到“ de”,你已经制定了一些法典,将分别孤立每个大米谷物,从而塑造形象。

关于计算具有黄色或绿色等特殊颜色的谷物的数量,再次通过 de读:大米的谷物与黄色或绿(或 o或ink)等小块不同颜色不相色。相反,大米谷物的颜色是专门制造的,因此,它们在整个彩色地图上平分。

So to proceed with your task you re going to have to provide some definition of yellow or green , perhaps in terms of being within a particular range of RGB values.

Having done this, you can then use the variable labeled (that is constructed for you in the demo) together with the regionprops command, to give you a list of the pixels that are within each rice grain boundary. Simply compare those pixels to your definitions of yellow or green, and you re there.

Answer 2

假设您在矩阵表a上有一个形象(大小m*n*3),你想找到有色标的物体序号<>[r,g,b]。

first, select only pixels with the correct color:

bb = (a(:,:,1) == r & a(:,:,2) == g &a(:,:,3) == b);

Than:

[~,num] = bwlabel(bb,8)

<代码>num为物体数目。

Answer 3

This is best done by working in a different colorspace than the RGB one (think HSV, Lab*, ..).

Steve Eddins 刊登了一系列文章,说明如何从图像中分离某些颜色的物体(绿色涂料;Ms in his case):

mms

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