Question

我知道,Lucene 文件说

Note: The NOT operator cannot be used with just one term. For example, the following search will return no results:

NOT “jakarta apache”

然而,我要提出一个问题,即归还所有载有任期的文件。我研究了一起铺设。 href=

If I index the following two documents

Doc0: content:The quick brown fox jumps over the lazy dog.
Doc1: (empty string)

查询<代码>*:* -content:fox在我只想一份文件时将这两份文件退回。

The RegexQuery content:^((?!fox).)*$ suggested by this StackOverflow answer returns one document but it does not seem to be working correctly because content:^((?!foo).)*$ returns one document as well when I expect it to return two documents.

我知道我想要做的工作对业绩的影响。问询只能用几份文件处理,因此我对业绩不感到担忧。

是否有办法撰写卢塞恩的问询,以获得我想要的东西?

Answer 1

您可以使用与一切相匹配的术语,并排除以下术语:

IndexSearcher searcher = new IndexSearcher("path_to_index");
MatchAllDocsQuery everyDocClause = new MatchAllDocsQuery();
TermQuery termClause = new TermQuery(new Term("text", "exclude_term"));
BooleanQuery query = new BooleanQuery();
query.add(everyDocClause, BooleanClause.Occur.MUST);
query.add(termClause, BooleanClause.Occur.MUST_NOT);
Hits hits = searcher.search(query);

Else, have a dummy field which some fixed value and use query

+dummy_field:dummy_value -exclude_term

Answer 2

您是否可以把“人工”引向每份文件,然后寻找“附加的,而不是你想要避免的”。

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