Question

Am getting an undeclared identifier problem in my code. Have commented the compiler messages.

Main.m

#import <Foundation/Foundation.h>

int main (int argc, const char * argv[])
{

     @autoreleasepool {

         NSMutableArray *stocks = [[NSMutableArray alloc]init];

         NSMutableDictionary *stock;

        stock = [NSMutableDictionary dictionary];
        [stock setObject:@"AAPL" 
                  forKey:@"symbol"];

        [stock setObject:[NSNumber numberWithInt:200]
                                        forKey:@"shares"];
                                [stocks addObject:stock];

         stock = [NSMutableDictionary dictionary];
         [stock = setObject:@"GOOG" // use of undeclared identifier  setObject 
                     forKey:@"symbol"];
         [stock = setObject:[NSNumber numberWithInt:160] // use of undeclared identifier      setObject 
                  forKey:@"shares"];
        [stocks addObject:stock];

        [stocks writeToFile:@"/tmp/stocks/plist" 
                 atomically:YES];



        }
    return 0;
}

Answer 1

你的问题是平等的。

 [stock **=** setObject:@"GOOG" // use of undeclared identifier  setObject 
                 forKey:@"symbol"];
     [stock **=** setObject:[NSNumber numberWithInt:160] // use of undeclared identifier      setObject 
              forKey:@"shares"];

你的法典应该是这样。

 [stock  setObject:@"GOOG" // use of undeclared identifier  setObject 
                 forKey:@"symbol"];
     [stock  setObject:[NSNumber numberWithInt:160] // use of undeclared identifier      setObject 
              forKey:@"shares"];

Answer 2

您没有

<代码>[stock = setObject...>。

页: 1

这些方法不会恢复任何价值,而是无效的方法(涉及――目标方法)。

Answer 3

页: 1 目的不是单纯的[原料:平等者”。

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