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在使用JPQL的模式中选择最容易的方式
原标题:Easiest way to select within a model using JPQL

我拥有三个模型的保密数据库:

Article - which has is part of multiple categories (EDIT).
Category - which contains articles, and is part of an App
App - which has different categories

I want to select all articles which have a category of a specific app. So I am trying to create something like:

find("ANY categories.app = ?", app).fetch();

与此类似,我与核心援助公司合作,但显然与联合援助机构不合作,我似乎无法找到如何做到这一点。

Edit: To clarify: in Articles:

    @ManyToMany
    public List<Category> categories;

类别:

    @ManyToOne
    public App app;

    @ManyToMany(mappedBy = "categories")
    public List<Article> articles;

适用:

    @OneToMany(mappedBy = "app")
    public List<Category> categories;
最佳回答
select a from Article a where a.category.app = ?

http://docs.jbos.org/hibernate/core/3.6/vis/en-US/html_single/#queryhql”rel=“nofollow”http://docs.jboss.org/hibernate/core/3.6/vis/en-US/html_single/#queryhql

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