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Closed 11 years ago.

STL为什么不包含无约束的分类数据类型?

I feel like it s a data type whose purpose is similar to that of a string.
Programmers would not have to worry about overflowing values and could work with much larger numbers.

因此,如果存在缺席的具体原因,我会感到奇怪。

This isn t an issue on how to implement or use one from a 3rd party library, but just a question as to why the language doesn t already come with one. Any links on the matter are appreciated.

Answer 1

也许意味着任意精确度:或大数。

也许这不是C++,因为它与广大受众无关。很可能,几乎所有非属地的C++代码都将使用STL部分(std:ostream或像std:vector这样的收集: 或诸如<代码>的类型:载。

但许多法典并不需要大量。

同样,由于同样的原因,制图接口(如Qt)不属于STL的一部分。许多人不关心这些问题(例如服务器代码或数字应用)。

界定一个标准图书馆是一项重大努力。我认为,C++ STL或许已经太大了;没有必要在内部增加很多东西。

如果需要,你不妨使用。

Answer 2

Because even way back when the STL was designed:

There were already significantly better arbitrary precision integer libraries in C. Sure they weren t officially classes, but the structures they used still did the job. An STL implementation wouldn t really get a great deal of uptake from those who need arbitrary precision integers, which leads me to my second reason:

并非许多人实际上需要任意的精确度。那些这样做的人在第三方图书馆里开车。对大多数32个年龄段的人来说,这些日子的工作是这样。对许多人来说,他们仍然这样做。业绩大大提高。即便是在没有本地64比特操作的系统中,你也可以用一些指示对他们进行模拟,而且仍然大大快于任意进行分类(不管你如何使这种制度变得软弱无力,任意部分和可能分配得过高,都会使其比两次低廉的分类作业和手工操作更加昂贵)。

不仅如此,圣鲁斯特鲁普才认为,它有广泛的呼吁,以适应他对《刑法》的看法。

我认为,一个更好的问题是,为什么在STL中,没有货币或任意的精准等级,因为我认为这是一个非常常见的问题,但答案是一样的。

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