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在C和C++中,为什么这种“主要”功能的积累从来不会超支?
原标题:In C and C++, why does this `main` function with an incrementing integer never overflow?

In C and C++, the most basic main function for embedded is:

int main(void) {
    int i = 0;

    while(1) {
        i++;
    }
}

但是,由于<条码>i是一种 in,在某个时候赢得过份?

另外,在等待具体中断时使用同样的战术(使用<条码>,同时(1) i)是否安全?

问题回答

http://strong>does 超出具体执行方式。

An implementation that defines signed integer types as also being modulo need not detect integer overflow

All modern computers define signed integers as modulo.

I would take this approach:

#include <stdio.h>
#include <stdint.h>

int main()
{
    uint16_t i = 1;

    while(i>0)
    {
        i++;
    }
    printf("i overflowed at: %u  sizeof(i): %u
", i-1, sizeof(i));
    return 0;
}




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