我有这样的观点:
SELECT dbo.FBAShipmentItems.ShipmentID, dbo.FBAShipmentItems.FNSKU, dbo.FBAShipmentItems.ASIN, dbo.FBAShipmentItems.Merchant,
dbo.FBAShipments.ShipmentName, dbo.FBAShipments.Prep_Type, dbo.FBAShipmentItems.Quantity
FROM dbo.FBAShipmentItems INNER JOIN
dbo.FBAShipments ON dbo.FBAShipmentItems.ShipmentID = dbo.FBAShipments.ShipmentID
问题在于,在我拥有近900件“快车道”物品和51件“快车道”物品时,它只显示出56项成果。 我如何看待所有900项成果
使用<代码>LEFT JOIN而不是 INNER JOIN:
SELECT
items.ShipmentID,
items.FNSKU,
items.ASIN,
items.Merchant,
shipments.ShipmentName,
shipments.Prep_Type,
items.Quantity
FROM dbo.FBAShipmentItems AS items
LEFT JOIN dbo.FBAShipments AS shipments
ON items.ShipmentID = shipments.ShipmentID
这将从FBAShipments上调来的对应浏览量,如果有的话,该表中所有数值均以其他方式计算。
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