Question

im using a AJAX request to get value from the server in a JSON format. but when i try to show this in the Ext.List only 1 value shows up instead of all.

Ext.setup({
onReady: function() {

    Ext.regModel( Contact , {
        fields: [ firstName ,  lastName ]
    iii
            var posts;
            var count;
            var name =  sdf ;
      Ext.Ajax.request({
                    url:  a.php/pool/listPools ,
                    method:  post ,
                    type: json ,
                    success: function(response){
                          posts = Ext.decode(response.responseText);
                          alert(response.responseText);
                          count = posts.count;
                          for (var i = 0; i < count; i++) {
                          name = posts.data[i].name;
                          alert(name);
                          var btnContact = new Ext.TabPanel({
        fullscreen: true,
        items: [ new Ext.List({
                            itemTpl:  ,
            title:  My Tab ,
            tpl:  <tpl for="."><div class="contact"><strong>{firstName}</strong> {lastName}</div></tpl> ,
            itemSelector:  div.contact ,
            singleSelect: true,
            grouped: true,
            indexBar: false,


            store: new Ext.data.JsonStore({
                model:  Contact ,
                sorters:  firstName ,

                getGroupString: function (record) {
                  return record.get( firstName );
                },
                data:  [
                    {
                                                firstName: name,
                                                lastName:   
                                            }
                ]
            })
        }), 
                     //{ title:  Tab 2  } 
                ]   
                    iii

                }}               
            iii

}

iii

我的问题是,如何显示所有检索的数据? 而不是仅仅1?

Answer 1

你们正在铺平路面铺设你的塔巴托,每组铺设一个塔巴托,每个塔巴托都有一个单一记录储存的清单。这一切都站在一起,因此,你只看到一个时候。

为了迅速开展这项工作,我将在座右边外围建立塔巴托,并在其内部建立你的数据集:

var dataArray = [];
for (var i = 0; i < count; i++) {
   name = posts.data[i].name;

   dataArray.push({
                   firstName: name,
                   lastName:   
              });
}

然后,你可以把这一数据传送给你的仓库:

new Ext.data.JsonStore({
            model:  Contact ,
            sorters:  firstName ,

            getGroupString: function (record) {
              return record.get( firstName );
            },
            data:  dataArray
        })

不过,我建议,你研究如何使贵店装上这一数据本身(通过轴心),因为这是这样做的最佳途径。

斯图尔特

友情链接