Question

I love/hate the regex because of usefulness/hardness. (I don t why but I can t construct pattern :( )
I have some records in my database field like this

[(ip1=192.x.?100)(id1=125485smds65)(date1=11.02.2011-1 5/15.06.2012-17:30)text1=Some text,其中可包括所有括号和(或)括号;任何果园等等;(案文}、[任何]{......]**) [(ip2=x.x.20.num)(2=12358(文本2=其他词):]



奥克,我希望返回一个具有价值阵列;
。

$result[ip1] = 192.x.?.100;
$result[id1] = 125485smds65;
$result[date1] = 11.02.2011-15:00/15.06.2012-17:30;
$result[text1] = Some text that can include all brackets and/or parentheses & any chars etc, like < ( text . } , [ any ) ] { etc.**;
$result[ip2] = 192.x.?.100;
$result[num2] = 1235845;
$result[text2] = many other words :)


您可以认为,括号内和括号中的数据数目可能有所不同。

因此,在收集上述数据之前,究竟是哪种情况?

Answer 1

类似情况:

$s =  (ip1=192.x.?.100)(id1=125485smds65)(date1=11.02.2011-15:00/15.06.2012-17:30)
(text1=Some text that can include all brackets and/or paranthesis & any chars etc, 
like < ( text . } , [ any ) ] { etc.**)][(ip2=x.x.20.?)(num2=1235845)
(text2=many other words :)) ;

preg_match_all( /((?:[^()]|(?R))*)/ , $s, $matches);

print_r($matches);

印刷:

Array
(
    [0] => Array
        (
            [0] => (ip1=192.x.?.100)
            [1] => (id1=125485smds65)
            [2] => (date1=11.02.2011-15:00/15.06.2012-17:30)
            [3] => (text1=Some text that can include all brackets and/or paranthesis & any chars etc, 
like < ( text . } , [ any ) ] { etc.**)
            [4] => (ip2=x.x.20.?)
            [5] => (num2=1235845)
            [6] => (text2=many other words :)
        )

)

in the regex patterns /(?:[^(>>>?R]/?

你们在问题下的评论清楚表明:在生产法典中不建议使用这种reg。我的建议是而不是储存你的数据,就像你在你的数据库中所做的那样。从根本上解决问题,请!

Answer 2

你可以做到:

/((([^)=]*)=([^)]*)))*/

然而,这是不可能的“可以包括所有括号和(或)底线的一些案文”——在世界上,你如何将案文与封闭的括号区分开来?

And in case this is a very poor data structure. First of all it s a database - it has columns, use them! Second, why are you rolling your own datastructure? You can use json, or php s serialize().

劳动局是这项工作的错误工具。

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