Question

我有以下联合材料:

$( form ).live( submit , function (event) {

                    // Stop the form from doing a native postback
                    event.preventDefault();

                    $.ajax({
                        type:  POST ,
                        timeout: 5000,
                        url: $(this).attr( action ),
                        data: $( form ).serialize(),
                        success: function (responseHtml) {

                            $.getJSON($(this).attr( action ), function (data) {

                                console.log(data);

                            });

                        },
                        error: function (jqXHR, textStatus, errorThrown) {

                            alert( server error );

                        }
                    });
                });

谁应当将json从下列微粒方法中记录下来(,意思是一 log倒,而不是一ja误!):

 [HttpPost]
        public JsonResult Login(User user, string returnUrl)
        {
            // Validate the email and password
            if (users.Login(user.UserName, user.Password, Request.UserHostAddress))
            {
                FormsAuthentication.SetAuthCookie(user.UserName, true);

                // build redirectUrl ...
                //var redirUrl = ...
                return Json(new { uservalidated = true, url = false });
            }
            else
            {
                return Json (new { uservalidated = false, url = false });
            }
        }

如果我不同意联合材料,那么我会看到结果的罚款,但出于某种原因,联合材料会发现:

Answer 1

认为你必须有Json RequestBehavior。允许

return Json(....., JsonRequestBehavior.AllowGet);

此外:

如果你使用新闻 ChromeF12和网络,Pebug在Emland,看看你是否收到404、500或类似的错误,说明为什么没有发生。

Answer 2

。

您需要储存一个参考文件this,以促成关闭

$( form ).live( submit , function (event) {
        // Stop the form from doing a native postback
        event.preventDefault();
        var self = this; // add this so you have a reference to this in callbacks
        $.ajax({
            type:  POST ,
            timeout: 5000,
            url: $(this).attr( action ),
            data: $( form ).serialize(),
            success: function (responseHtml) {

                $.getJSON( $(self).attr( action ) , function (data) {

                    console.log(data);

                });

            },
            error: function (jqXHR, textStatus, errorThrown) {

                alert( server error );

            }
        });
    });

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