Question

I m trying to encrypt a string with rijndael (keysize 256 bit, blocksize 256 bit, CFB mode) currently i m doing something like this:

BufferedBlockCipher c = new BufferedBlockCipher(new CFBBlockCipher(new RijndaelEngine(256), 256));
    c.init(false, new ParametersWithIV(new KeyParameter(keybytes), iv));

我可以进行加密和加密,而我自己的脚.只是罚款。不幸的是,必须加以加密的地体源自于实验室的加密。

I cant decrypt this string and i guess the failure is on my side. could anybody give me an example how to configure a cipher with the required parameters?

http://www.un.org。

遵循此处和在网址文件评论中的一些建议。 i 改变我的圈子:

PaddedBufferedBlockCipher c = new PaddedBufferedBlockCipher(new CFBBlockCipher(new RijndaelEngine(256)), new ZeroBytePadding());

加密仍不兼容。

<EDIT 2

它采用CBC模式开展工作。我猜想这个问题在四处。

Answer 1

PaddedBufferedBlockCipher c = new PaddedBufferedBlockCipher(new CFBBlockCipher(new RijndaelEngine(256), 8), new ZeroBytePadding());
c.init(false, new ParametersWithIV(new KeyParameter(keybytes), iv));

这确实是骗局。所有的事例和辅导都说,CFBBlockCipher物体的第二段是ch块,它将发挥作用,但微粒为CFB使用8块块。

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