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在要求页数时发现错误
原标题:Getting error when pages are being requested

我有一人在小地点修建了海关编码管理系统,现在我可以让开发商持有。 我在试图查看我的现场时,会发现这一错误:

You have an error in your SQL syntax;
check the manual that corresponds to your MySQL server version
for the right syntax to use near  order by sortorder  at line 1:

select path, title
from pages
where parent_id =
order by sortorder

帮助 我认为,问题在于:

public function getChildLinks()
{
    $list = array();
    $WHERE_path = substr($_SERVER[ REQUEST_URI ], 1);
    $WHERE_path = strlen($WHERE_path) ?  = " .$WHERE_path. "  :  IS NULL ;
    $parentPageRowset = Axl_Db::query( SELECT id, parent_id FROM  .$this->_name.  WHERE path  .$WHERE_path);
    $parent_id = $parentPageRowset[0][ parent_id ] ? $parentPageRowset[0][ parent_id ] : $parentPageRowset[0][ id ];
    $listRowset =  new Axl_Db_Rowset( SELECT path, title FROM  .$this->_name.  WHERE parent_id =  .$parent_id.  ORDER BY sortorder );
    while($listRowset->next())
    {
        $list[ / .$listRowset->path] = $listRowset->title;     
    }
    return $list;
}

This is the function causing the problem.

最佳回答

在从Adam I获得大量饲料之后,我能够真正地指出,我需要做些什么,才能确定和看一看更深的东西。

由此可见,我需要引证父母的错误。

同样:

$listRowset =  new Axl_Db_Rowset( select path, title from  .$this->_name.  where parent_id = " .$parent_id. " order by sortorder );

感谢亚当帮助

问题回答

问题与你的<代码>有关。 WHERE 条款;它有<条码> 括号_id = ,但没有下文。 你们需要为问题提供价值。

移民归化局比可能更需要高档期的工薪,以便我方言发挥作用。





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