Question

例如,我去街面“1234 West 23rd Street”。我只想打上第一个街号,在每一街号之间放下空间,如“1 2 3 4 West 23rd Street”。

Using the simple expression like "([0-9])" and replacing it with "$1 " almost works, except I want it to stop after the first space and not match, per the above example, the "23" in "23rd" as well.

Answer 1

This is possible with preg_replace and the pattern modifier e , which:

replacement str str in substitution substitution substitution of as as as as

$str =  1234 West 23rd Street ;
preg_replace( /^([[:digit:]]+)/e , "implode(   , str_split( $1 ))", $str);
// returns  1 2 3 4 West 23rd St

Answer 2

你再次需要PHP帮助你来到这里,你只能与Regex一起这样做(Regex不会像这种情况那样做,而是没有为之设计)。

与此相匹配:([0-9]+]s,然后由您获得(如果只有一个以上,可能只是使用第一个结果),添加了您在每种特性之间所希望的空间。

Answer 3

因此,你只想对位数和空间之后的数值进行对比。您可使用<代码><>>>/代码>,与线的开始相吻合。因此,你可以研究这样的情况:

^(d+)

<代码>d与任何数字对应。

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