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Closed 10 years ago.

$newHTML = str_replace("<tr><td>1-30 of 699 results.1 | 2 | 3 | 4 | 5 | 6 | 7 | 8-15 &Acirc;&middot; Next &Acirc;&middot; Last</td></tr>", "", $newHTML);
            $newHTML = str_replace("<tr><td>31-60 of 699 results.First &Acirc;&middot; Prev &Acirc;&middot; 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8-15 &Acirc;&middot; Next &Acirc;&middot; Last</td></tr>", "", $newHTML);
            $newHTML = str_replace("<tr><td>61-90 of 699 results.First &Acirc;&middot; Prev &Acirc;&middot; 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8-15 &Acirc;&middot; Next &Acirc;&middot; Last</td></tr>","",$newHTML);
            $newHTML = str_replace("<tr><td>91-120 of 699 results.First &Acirc;&middot; Prev &Acirc;&middot; 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8-15 &Acirc;&middot; Next &Acirc;&middot; Last</td></tr>","",$newHTML);
            $newHTML = str_replace("<tr><td>121-150 of 699 results.First &Acirc;&middot; Prev &Acirc;&middot; 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8-15 &Acirc;&middot; Next &Acirc;&middot; Last</td></tr>","",$newHTML);

上面的法典是我没有做的事,因为我根本不理解。

**<tr><td>**121-150 **of 699 results.First &Acirc;&middot; Prev &Acirc;&middot; 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8-15 &Acirc;&middot; Next &Acirc;&middot; Last</td></tr>**

上文以121-150为例,是<代码>新超文本中唯一固定数字。其他扼杀似乎是多次发生的。我怎么能抛弃这些景点? 页: 1

<tr><td>###-### of 699 results.First &Acirc;&middot; Prev &Acirc;&middot; 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8-15 &Acirc;&middot; Next &Acirc;&middot; Last</td></tr>

如果有迹象,需要删除。

Answer 1

简单直截了当地将你的一套扼杀物转换为一种PHP经常表达。这些考虑是:

位数为1位或1位以上,因此,位数以内。

<代码>>/代码>为垂直线,因此你可以代替每一垂直线。

因此,与规定的一套指示相对应的定期表述是:

<tr><td>d+-d+ of d+ results.First &Acirc;&middot; Prev &Acirc;&middot; 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8-15 &Acirc;&middot; Next &Acirc;&middot; Last</td></tr>

友情链接