I have an array of 6 ints that I am interested in getting a hash value for (an int). I am wondering if there is a relatively strong and fast hash function for this case which is implemented in Java.
我几乎想把这6个插头改为“强硬”(如每条单条编码性质,或像这样,不代表每个星号作为实际数字)和使用“印花编码”,但对于我来说,它非常低效,我认为需要更快一些。 任何想法?
Thanks.
int[] myIntArray = {1, 2, 3, 4, 5};
int myHashCode = Arrays.hashCode(myIntArray);
注:Arrays有hashCode()适用于所有原始类型,而不仅仅是帐篷。
还有一点告诉我,你将再使用6个号码的序列作为通行证编码,并用斜体与之匹配。 在这种情况下,你会再次要求真正、真正长久的洗衣。 至少提前24小时,而不是4位 in子会给你。 (拥有比你投入空间更大的散射空间将减少碰撞。)
d 前往SHA-384或以上。 不要忘记盐类。
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