create table foo (id, name)
create table bar (id, name)
create table foo_bars (foo_id, bar_id)
将外国关键关系添加到许多对手表是否有意义。 我假定,我们需要一种家庭-家庭关系,以便在 f-酒吧进行 f和酒吧。 谁能证实?
是的,你们需要外国钥匙来确保数据的一致性。
它具有许多意义。 。
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