Question

I m试图读一个显示数字和特性的插图。

Additional Info:
1. the program is showing 10 (ten) as 1 and 0 i.e two separate digits
2. It is also counting space as a character, which it should skip.
3. If a user input 10 20 + it should display:
digit is 10
digit is 20
other Character is +

Here is what I ve tried

#include <iostream>
#include <string>
using namespace std;

int main() {
    string s("10 20 +");
    const char *p = s.c_str();
    while (*p !=   )
    {
        if(isdigit(*p))
        {
            cout << "digit is: "<< *p++ << endl;
        }
        else
        {
            cout<<"other charcters are:"<<*p++<<endl;
        }

    }

    system("pause");
}

www.un.org/Depts/DGACM/index_spanish.htm Edit 现在改为:

#include <iostream>
#include <string>
using namespace std;

int main() {
               string x;
string s("1 2 +");
const char *p = s.c_str();
while (*p !=   )
{
while(isspace(*p)){
                   *p++;
      if(isdigit(*p))
      {
                     while(isdigit(*p))
                     {

                                 x+=*p++;
                                        cout << "digit is: "<< x<< endl;
            }

       }

       else{
            while(!isdigit(*p)&& !isspace(*p))
            x+=*p++;
            cout<<"other charcters are:"<<x<<endl;
            }
}
}
system("pause");
}

Not workingg

Answer 1

你们可以使用直截了当的方法。

[...]
stringstream ss;
ss << s;
while(!ss.eof())
{
    char c = ss.peek(); // Looks at the next character without reading it
    if (isdigit(c))
    {
        int number;
        ss >> number;
        cout << "Digit is: " << number;
    }
    [...]
}

Answer 2

虽然其特性是空间(在isspace功能上加以验证)。

如果目前的性质是一位数,则目前的性质是一位数把它放在临时位置上。当性质不再是数位数时,你有 > > /m>(可能只有一个 / 数>)。

Else if the character is not a digit or not a space, do the same as for numbers: collect into a temporary string and display when it ends.

Start over.

<><>Edit>/strong> 要求查阅的法典样本:

std::string expression = "10 20 +"; for (std::string::const_iterator c = expression.begin(); c != expression.end(); ) { std::string token; // Skip whitespace while (isspace(*c)) c++; if (isdigit(*c)) { while (isdigit(*c)) token += *c++; std::cout << "Number: " << token << " "; } else { while (!isidigit(*c) && !isspace(*c)) token += *c++; std::cout << "Other: " << token << " "; } }

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