页: 1 我如何从一个转变到另一个?
Hi have this j2ee web application developed using spring framework. I have a problem with rendering mnessages in nihongo characters from the properties file. I tried converting the file to ascii using ...
页: 1 我如何从一个转变到另一个?
您可使用Character.toString(char)。 请注意,这一方法只是向以下网站发出呼吁:String.Of(char)
,该编码也发挥了作用。
正如其他人指出的,扼杀 con还是一种捷径:
String s = "" + s ;
但是,这汇编成:
String s = new StringBuilder().append("").append( s ).toString();
which is less efficient because the StringBuilder
is backed by a char[]
(over-allocated by StringBuilder()
to 16
), only for that array to be defensively copied by the resulting String
.
下面的5> > > > > 6方法。
// Method #1
String stringValueOf = String.valueOf( c ); // most efficient
// Method #2
String stringValueOfCharArray = String.valueOf(new char[]{x});
// Method #3
String characterToString = Character.toString( c );
// Method #4
String characterObjectToString = new Character( c ).toString();
// Method #5
// Although this approach seems very simple,
// this is less efficient because the concatenation
// expands to a StringBuilder.
String concatBlankString = c + "";
// Method #6
String fromCharArray = new String(new char[]{x});
Note: Character.toString(char) returns String.valueOf(char). So effectively both are same.
<编码>String. ValueOf(char[] Value> 援引new String(char[] Value>
,后者反过来又规定了 Value
char range。
public String(char value[]) {
this.value = Arrays.copyOf(value, value.length);
}
另一方面,<代码> String. ValueOf(char Value) 援引了以下 Package private Constructionor.。
String(char[] value, boolean share) {
// assert share : "unshared not supported";
this.value = value;
}
String.java
in Java 8 source Code
因此,从记忆和速度来看,将<条码>/条码>改为<条码>。
来源:
下面是各种方式,以转换成果园(以降低速度和效率的速度)。
char c = a ;
String s = String.valueOf(c); // fastest + memory efficient
String s = Character.toString(c);
String s = new String(new char[]{c});
String s = String.valueOf(new char[]{c});
String s = new Character(c).toString();
String s = "" + c; // slowest + memory inefficient
使用以下任何手段:
String str = String.valueOf( c );
String str = Character.toString( c );
String str = c + "";
Use the Character.toString()
method like so:
char mChar = l ;
String s = Character.toString(mChar);
@WarFox说,有6种方法将果园改道。 然而,最快的办法是通过分类,尽管上文已经回答说它是<代码>。 String. ValueOf。 这里的基准证明:
@BenchmarkMode(Mode.Throughput)
@Fork(1)
@State(Scope.Thread)
@Warmup(iterations = 10, time = 1, batchSize = 1000, timeUnit = TimeUnit.SECONDS)
@Measurement(iterations = 10, time = 1, batchSize = 1000, timeUnit = TimeUnit.SECONDS)
public class CharToStringConversion {
private char c = c ;
@Benchmark
public String stringValueOf() {
return String.valueOf(c);
}
@Benchmark
public String stringValueOfCharArray() {
return String.valueOf(new char[]{c});
}
@Benchmark
public String characterToString() {
return Character.toString(c);
}
@Benchmark
public String characterObjectToString() {
return new Character(c).toString();
}
@Benchmark
public String concatBlankStringPre() {
return c + "";
}
@Benchmark
public String concatBlankStringPost() {
return "" + c;
}
@Benchmark
public String fromCharArray() {
return new String(new char[]{c});
}
}
And result:
Benchmark Mode Cnt Score Error Units
CharToStringConversion.characterObjectToString thrpt 10 82132.021 ± 6841.497 ops/s
CharToStringConversion.characterToString thrpt 10 118232.069 ± 8242.847 ops/s
CharToStringConversion.concatBlankStringPost thrpt 10 136960.733 ± 9779.938 ops/s
CharToStringConversion.concatBlankStringPre thrpt 10 137244.446 ± 9113.373 ops/s
CharToStringConversion.fromCharArray thrpt 10 85464.842 ± 3127.211 ops/s
CharToStringConversion.stringValueOf thrpt 10 119281.976 ± 7053.832 ops/s
CharToStringConversion.stringValueOfCharArray thrpt 10 86563.837 ± 6436.527 ops/s
如您所知,最快的是c + “
or >+ c
;
VM version: JDK 1.8.0_131, VM 25.131-b11
这一业绩差异是由于<代码>-XX:+OptimizeStringConcat优化所致。 https://stackoverflow.com/questions/42193955/why-is-string-concatenation-faster-than-string- Valueof-for-verting-an-integer>here。
引申:Character.toString(aChar)
or Just this:aChar + “
我们有各种办法将<条码>代谢/代码>改为<条码>。 <>One way is to make use of一个静止方法toString()
in Character
班级:
char ch = I ;
String str1 = Character.toString(ch);
实际使用<代码>至String方法 利用果园阵列的方法:
public static String toString(char c) {
return String.valueOf(c);
}
So second way is to use this directly:
String str2 = String.valueOf(ch);
* E/CN.6/2009/1。 缩略语
public static String valueOf(char c) {
char data[] = {c};
return new String(data, true);
}
因此,third >方法是使用匿名阵列,以包罗单一特性,然后将其通过至String
构造者:
String str4 = new String(new char[]{ch});
<>四><>>
String str3 = "" + ch;
这将实际上利用<代码>应用。 <代码>StringBuilder 类别,在我们进行整 lo时实际上更可取。
这里有几种方法,特别是:
char c = c ;
String s = Character.toString(c); // Most efficient way
s = new Character(c).toString(); // Same as above except new Character objects needs to be garbage-collected
s = c + ""; // Least efficient and most memory-inefficient, but common amongst beginners because of its simplicity
s = String.valueOf(c); // Also quite common
s = String.format("%c", c); // Not common
Formatter formatter = new Formatter();
s = formatter.format("%c", c).toString(); // Same as above
formatter.close();
I am converting Char Array to String
Char[] CharArray={ A , B , C };
String text = String.copyValueOf(CharArray);
char vIn = A ;
String vOut = Character.toString(vIn);
For these types of conversion, I have site bookmarked called https://www.converttypes.com/ It helps me quickly get the conversion code for most of the languages I use.
我研究了这些建议,但最后执行如下。
editView.setFilters(new InputFilter[]{new InputFilter()
{
@Override
public CharSequence filter(CharSequence source, int start, int end,
Spanned dest, int dstart, int dend)
{
String prefix = "http://";
//make sure our prefix is visible
String destination = dest.toString();
//Check If we already have our prefix - make sure it doesn t
//get deleted
if (destination.startsWith(prefix) && (dstart <= prefix.length() - 1))
{
//Yep - our prefix gets modified - try preventing it.
int newEnd = (dend >= prefix.length()) ? dend : prefix.length();
SpannableStringBuilder builder = new SpannableStringBuilder(
destination.substring(dstart, newEnd));
builder.append(source);
if (source instanceof Spanned)
{
TextUtils.copySpansFrom(
(Spanned) source, 0, source.length(), null, builder, newEnd);
}
return builder;
}
else
{
//Accept original replacement (by returning null)
return null;
}
}
}});
将<代码>char/code>改为String
。 String. ValueOf methods.
To convert a String
to a char
, you can use the String.charAt
method.
char character = a ;
String string = String.valueOf(character);
String string = "a";
char character = string.charAt(0);
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