Question

I have started writing an application that gets in a certain website and gets the information in the pages in a nicer cleaner way. My first problem is getting authenticated so I could download the pages. This is the site: https://www.ims.tau.ac.il/Tal/. It is in Hebrew but the top form goes (top to bottom): username, id number, password.

当我填写表格并点击SUBMIT但顿 I新闻社F12,见POST信息:

Request URL:https://www.ims.tau.ac.il/Tal/Login_Chk.aspx?rk=
Request Method:POST
Status Code:302 Found

Request Headersview parsed

POST /Tal/Login_Chk.aspx?rk= HTTP/1.1    
Host: www.ims.tau.ac.il    
Connection: keep-alive 
Content-Length: 82    
Cache-Control: max-age=0   
Origin: https://www.ims.tau.ac.il
User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/535.2 (KHTML, like Gecko) Chrome/15.0.874.120 Safari/535.2   
Content-Type: application/x-www-form-urlencoded    
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8    
Referer: https://www.ims.tau.ac.il/Tal/    
Accept-Encoding: gzip,deflate,sdch    
Accept-Language: en-US,en;q=0.8    
Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.3    
Cookie: ASP.NET_SessionId=2mi4i555jfibfb55wolrse55

Query String Parametersview URL encoded

rk:
Form Dataview URL encoded
user:MYUSERNAME
id_num:MYIDNUMBER
pass: MYREALPASSWORD
Enter.x:46
Enter.y:18
javatest:9
src:

Response Headersview parsed

HTTP/1.1 302 Found    
Date: Wed, 16 Nov 2011 21:25:46 GMT    
Server: Microsoft-IIS/6.0
X-Powered-By: ASP.NET    
X-AspNet-Version: 2.0.50727    
Location: Sys/Main.aspx?id=021653167&sys=tal&rk=&dt=16/11/2011 11:25:46 PM    
Cache-Control: private    
Content-Type: text/html; charset=utf-8   
Content-Length: 207

我试图从我在论坛其他岗位上发现的法典中抽出,但我无法工作:

public class MyTauRobot implements Runnable {

    private static final String TAG = "MyTauActivity";

    String name;
    String id;
    String pass;
    String result;

        public MyTauRobot() {
        super();
    }

    public MyTauRobot(String name, String id, String pass) {
        super();
        this.name = name;
        this.id = id;
        this.pass = pass;
    }

    @Override
    public void run() {
        HttpClient postClient = new DefaultHttpClient();
        HttpPost httpPost = new HttpPost("https://www.ims.tau.ac.il/Tal/Login_Chk.aspx?rk=");
        HttpResponse response;


        try {

            List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
            nameValuePairs.add(new BasicNameValuePair("user", name));
            nameValuePairs.add(new BasicNameValuePair("id_num", id));
            nameValuePairs.add(new BasicNameValuePair("pass", pass));

            httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

            response = postClient.execute(httpPost);

            if(response.getStatusLine().getStatusCode() == 200) {
                HttpEntity entity = response.getEntity();

            }           

            Log.v(TAG,EntityUtils.toString(response.getEntity())); 

        } catch (Exception e) {
            Log.d(TAG, e.toString());
            Log.d(TAG, e.getCause().toString());
            }
        }
}

当我执政时,我就有一个例外。

org.apache.http.client.ClientProtocolException
11-19 22:42:48.758: D/MyTauActivity(726): org.apache.http.ProtocolException: Invalid redirect 
URI: Default.aspx?id=&rk=&src=&dt=20/11/2011 12:42:48 AM

UPDATE: I still get an exception but I ve found out that atlist it seems to be logging in right the exception comes because the redirect is relative so i get "main.aspx?..." instead of "http://www.tau.ac.il/Tal/Sys/main.aspx?..."

如何确定?

org.apache.http.ProtocolException: Invalid redirect URI: Sys/Main.aspx?id=021653167&sys=tal&rk=&dt=25/11/2011 8:50:56 AM

Answer 1

我找到了解决办法。

问题是,服务器正在对相对间接和<代码>faultHttpClient作出答复。不能照此办理。这是自我确定违约以来的。 HttpClient:

this.getParams().setParameter(ClientPNames.REJECT_RELATIVE_REDIRECT, false);

但是,既然它没有工作,我就决定试图对一个绝对地址作相对的回答,而我也做了工作。

你们都必须:

1. 创建一种习惯转手器,超越getLocation:

class CustomRedirectHandler extends DefaultRedirectHandler {
    @Override
    public URI getLocationURI(HttpResponse response, HttpContext context)
            throws ProtocolException {
        response.setHeader("Location", "http://www.ims.tau.ac.il/Tal/"+ response.getFirstHeader("Location").getValue().replace(" ", "%20"));        
        return super.getLocationURI(response, context);
    }
}

不是“http://www.ims.tau.ac.il/Tal/”,而是写上你自己档案的绝对基点。

例如,需要。但是,服务器只是转向指数.html。您在“http://www.google.com/”上将服务器所在地的答复与上述代码相同。

BTW the server was replying with spaces which again DefaultHttpClient had problem with so you replace spaces with %20 to get it to work.

1. 确立你的违约/cus HttpClient to use the new redirecthandler as this:
```
httpClient.setRedirectHandler(new CustomRedirectHandler());
```

Answer 2

也许,它确实如此。检查 HttpResponse,如果你有 log,你可以进一步利用这一错误,而只是忽视这一错误。

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