Say 我想做的是,从档案名称(即档案名称)中分离出一个任择版本。
val regex(name, ver) = "file.jar" // name = file, ver = empty
val regex(name, ver) = "some-software.jar" // name = some-software, ver = empty
val regex(name, ver) = "software-1.0.jar" // name = software, ver = 1.0
val regex(name, ver) = "some-file-1.0.jar" // name = some-file, ver = 1.0
如何在Schala/Java撰写这种定期的表述? 顺便提一下,我会做一些事情:
(*)(-(<>>)*)?
但是,Schala并不支持在这一辛迪加设立任择团体。
我不肯定你现在的问题是什么。
我认为这不符合第二组,因为第一个组是贪.,而第二个组是选择性的,第一个组是完全相同的。
为此:
(.*?)(?:-(?=d)(.*))?.jar
See it here on Regexr
.*? (?:. You will find the name now in group 1 and the version in group 2.如何:
/^(.+?)(?:-([d.]*))?.jar$/
假设版本总是由数人和 do混在一起。
Recently I discovered two amazing regular expression features: ?: and ?!. I was curious of other neat regex features. So maybe you would like to share some tricky regular expressions.
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