Question

采用肿瘤透镜和以下代码:

$var = xhttp::toQueryArray($response[ body ]);
print_r($var);

这部插图如下:

Array ( [{"meta":{"status":200,"msg":"OK"},"response":{"user":{"name":"lukebream","likes":0,"following":8,"default_post_format":"html","blogs":[{"name":"lukebream","url":"http://lukebream.tumblr.com/","followers":5,"primary":true,"title":"Untitled","admin":true,"queue":0,"ask":false,"tweet":"N"}]}}}] => )

我如何能够接触各个要素,把它们归入变量?

这里是我完成的:

$tumblr->set_token($_SESSION[ oauth_token ], $_SESSION[ oauth_token_secret ]);
$data = array();
$data[ post ] = array();        
$response = $tumblr->fetch( http://api.tumblr.com/v2/user/info , $data);    

if($response[ successful ]) {
    echo $response[ json ][ response ][ url ];
} else {
    echo "api call failed. {$response[body]}<br><br>";
}

Answer 1

http://en.wikipedia.org/wiki/JSON"rel=“nofollow”>,JSON >/a>。

www.un.org/Depts/DGACM/index_spanish.htm Usage Example :

//I used file_get_contents() to keep things simple
$jsonData = file_get_contents("http://api.tumblr.com/v2/blog/lukebream.tumblr.com/info?api_key=<api_key_here>");

The$jsonData contained:

{
    "meta":{
        "status":200,
        "msg":"OK"
        },
    "response":{
        "blog":{
            "title":"Untitled",
            "posts":61,
            "name":"lukebream",
            "url":"http://lukebream.tumblr.com/",
            "updated":1321830278,
            "description":"",
            "ask":false,
            "likes":0
            }
        }
}

在通过<代码>json_decode()之后,我们获得了一种PHP物体,因此:

$obj = json_decode($jsonData);

返回:

stdClass Object
(
    [meta] => stdClass Object
        (
            [status] => 200
            [msg] => OK
        )
    [response] => stdClass Object
        (
            [blog] => stdClass Object
                (
                    [title] => Untitled
                    [posts] => 61
                    [name] => lukebream
                    [url] => http://lukebream.tumblr.com/
                    [updated] => 1321830278
                    [description] => 
                    [ask] => 
                    [likes] => 0
                )
        )
)

然后,你可以与其他物体一样获得数据。

Answer 2

你们也可以使用json_decode($str, TRUE):这将退回ARRAY,而不是一个物体,更容易与!

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