Question

我有这样的档案。

/device/000:004:00.7/vmkname = "vmnic8"

/device/000:005:00.0/vmkname = "vmnic0"

/device/000:005:00.1/vmkname = "vmnic4"

/device/000:005:00.2/vmkname = "vmnic10"

/device/000:005:00.3/vmkname = "vmnic11"

......15行

我愿作如下改动:

/device/000:004:00.7/vmkname = "vmnic0"

/device/000:005:00.0/vmkname = "vmnic1"

/device/000:005:00.1/vmkname = "vmnic2"

/device/000:005:00.2/vmkname = "vmnic3"

......

/device/000:005:00.3/vmkname = "vmnic15"

Answer 1

perl -pe  s/d+(")$/$i++.$1/e;  file

。

Answer 2

Awk edition:

awk  {if ($1) {print $1, $2, ""vmnic"c++"""}else{print}}  FILE

您可将产出转用于新的档案。

Answer 3

This should do:

count=0
for i in `cat input_file.txt | cut -d " " -f1`
do
    echo $i = "vmnic$count" >> output_file.txt
    count=`expr $count + 1`
done

Just make sure your input_file.txt doesn t have any empty lines.

Answer 4

见:

#!/bin/bash

c=0
while read a b; do
    [[ "$a" ]] || continue
    echo "$a = "vmnic$((c++))""
done < FILE > NEW_FILE

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