Question

public int compareTo(Object o) {
    Doctor d = (Doctor)o;
    return (doctor_name.compareTo(d.doctor_name));
}

这是我对博士学位的对比。

jTextArea.setText("");
int doctor_id = Integer.parseInt(jTextField2.getText());
String doctor_name = jTextField3.getText();
String hospitalName = jTextField4.getText();

Doctor d = new Doctor(doctor_id,doctor_name,hospitalName);
hmDoctor.put(doctor_id, d);

This is my hashmap

这是我的树图。

TreeMap<Integer,Doctor> tmDoctor = new TreMap<Integer,Doctor>(hmDoctor);
jTextArea.setText("");
Set keys = tmDoctor.keySet();
Iterator<Integer> ite = keys.iterator();

while(ite.hasNext())
{
    int doctorID = ite.next();
    Doctor d = tmDoctor.get(doctorID);
    tmDoctor.put(doctorID, d);
    jTextArea1.append(d.toString());
}

它没有医生的姓名。为什么?

Answer 1

The TreeMap sorts elements according to their keys, not values. As an alternative, you could use a TreeMap<String, Doctor> indexed by the doctor s name. Or, depending on what you need to do, you can just keep the doctors in a TreeSet.

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