Question

我应从记本中拿到身份证,但该法典没有给出正确的说法。谁能告诉我,我的法典中有什么错误? (详情见下文)

for (int i = 0; i < numberOfSRecords; i++) {
    socketReader.read(cbuf, 0, 4);
    String Param_Codes_In_HEX =
        Integer.toHexString(0x000000ff & cbuf[2]) +
        Integer.toHexString(0x000000ff & cbuf[1]) +
        Integer.toHexString(0x000000ff & cbuf[0]);
    System.out.println("Param_Codes_In_HEX: "+Param_Codes_In_HEX);
    int paramCode = Integer.parseInt(Param_Codes_In_HEX, 16);
    if ((0x000000ff & cbuf[3]) ==0) {
    EnumParamCodes enumParamCode = 
         EnumConverterUtil.getEnumFor(EnumParamCodes.class, paramCode);
    System.out.println("Param_code " + paramCode + ": " + enumParamCode);
    }
  else if((0x000000ff & cbuf[3]) ==64)
   {
    paramCode = 0x0000ffff & paramCode ;
    EnumParamCodes enumParamCode = EnumConverterUtil.getEnumFor(EnumParamCodes.class, paramCode);
   System.out.println("Param_code " + paramCode + ": " + enumParamCode);
   }
  else if ((0x000000ff & cbuf[3]) ==128) {
      paramCode = 0x00ffffff & paramCode ;
      EnumAlarm enumParamCodeAlarm = EnumConverterUtil.getEnumFor(EnumAlarm.class, paramCode);
      System.out.println("Param_code " + paramCode + ": " + enumParamCodeAlarm);
    } 
  else{
      System.out.println("Error in the body of message");
        }
      }

Note: • For Numerical and Enumerative Parameters (ActualValue), the Param_code corresponds to the ID in the Parameters section

• For Numerical and Enumerative Parameters (SetValue), the Param_code corresponds to 0x40000000 + the ID in the Parameters section

• For Alarm Parameters, the Param_code corresponds to 0x80000000 + the ID in the Parameters section

Answer 1

String getByteString(byte b) {
    StringBuffer buf = new StringBuffer();
    String digit=Integer.toHexString(b &0xff);
    buf.append(digit);
    if (digit.length()<2) buf.append( 0 );
    return buf.toString();
}

这应当为你们带来 0。

String Param_Codes_In_HEX = getByteString(cbuf[2]) + getByteString(cbuf[1]) + getByteString(cbuf[0]);

Answer 2

守则对于它正在做的事情来说相当复杂。其中一个问题是,在你想要做比喻的操纵时,可能会试图进行分类。 e. 例如,1 233先令将变成123而不是010203。

友情链接