Question

Im试图制造一种使用这三种公式的流速计算器。

压力比率 b

b = p2 +0.1 / p1 +0.1

The C-value and B-Value are given numbers depending on the valve. See page 6 on this pdf http://content2.smcetech.com/pdf/SY.New.pdf

问题长期流动

Q = 600 * C(p1 +0.1) sqrt(293/(273 +t)

This is my working code.

float pressure1 = ([pressureMPa.text floatValue])+ 0.1;
float c = 600 * ([cValue.text floatValue]);
float temperature = ([tempC.text floatValue]);
float root = sqrtf(293/(273+temperature));
float sonicFlow = c * pressure1 * root;

Q = flow rate l/min
C = dm^3/s * bar
p1= Supply pressure: MPa
t = temperature deg C

长期流动

Q = 600 * C(p1 +0.1)* sqrt (1-(p2+0.1/p1 +0.1 - b 1-b)^2* sqrt(293/(273+t)

Q = flow rate l/min
C-value = dm^3/s * bar
p1 Supply pressure: MPa
t temperature deg C
b-Value

What is the best way to write the subsonic flow code?

页: 1 我有问题。

Answer 1

很难看到你所再次提出的问题。是否需要由辛迪加来做真正的根基和权力?

Square root: sqrtf(float)
Power: powf(float, float) - second float is the power you want to raise the first float to.

两种电能(或许更容易阅读)的简单易行之处在于先计算中间值,然后乘以:

<代码>价值A * 价值A。

此外,铭记在C. 推广、各司和模块内容的操作者优先程度方面需要小心谨慎,然后进行增减。如你所领导的“瓦克斯特”所建议的那样,确保你适当或更妥善地在方括号中总结事情,采取多种步骤进行计算。因此,就你而言,我们担心:

// sqrt((1-((p2+0.1)/(p1+0.1))-b) / (1-b))^2
float part1 = (p2 + 0.1) / (p1 + 0.1);
float part2 = (1 - part1 - b) / (1 - b);
float part3 = sqrtf(part2);
float result = part3 * part3;

part1/2/3 are perhaps not ideal variable names, but you get the idea.

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