我有以下法典:
$open_socket = fsockopen($host,$port,$errno,$errstr,30);
if(!$open_socket){
echo "$errstr ($errno)<br />".$nl;
}else{
fputs($open_socket,$xml);
while(!feof($open_socket)){
$line = fgets($open_socket,128);
$return_xml.= $line;
}
fclose($open_socket);
}
但如果没有联系,我收到以下信息:
警告:
该网页的其余部分是空白的,基本上我如何能够在我的网页上继续播放,只展示错误信息,而不是发出警告。
增 编
你们可以提出警告,呼吁开裂
$open_socket = @fsockopen($host,$port,$errno,$errstr,30);
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