我不想这样做,但返回却无效?
$query_1=$field_name[0]."= {".$field_value[0]."} ";
之后
getType = mysql_query("SELECT * FROM wines WHERE $query_1") or die(mysql_error());
虽然如此:
$getType = mysql_query("SELECT * FROM wines WHERE $field_name[0]= {$field_value[0]} ") or die(mysql_error());
罚款。
is this even possible, or am I missing something too obvious? thank you in advance!
你们正在以错误的方式来加以建设。 您永远不应在座标中使用曲解的括号(或任何其他插图)。 相反,请你回答。
与此类似:
$query_1=$field_name[0]."= ".$field_value[0]." ";
并且,你在问询之前错过了一笔美元,这说明为什么它无效。
对我来说,这项工作是:
$field_name[0] = "test";
$field_value[0] = "someting";
$query_1=$field_name[0]."= ".$field_value[0]." ";
echo ("SELECT * FROM wines WHERE $query_1") or die(mysql_error());
希望会有助于
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