我需要通过一个文本档案,并检查每条线路的开端是否始于“阿蒂鲁特”。 我如何在VB6中这样做?
Win.ShellExecute 0, "open", "C:dirprogram.exe", "arguments", vbNullString, SW_SHOWNORMAL Win.ShellExecute 0, "open", "http://www.google.com", vbNullString, vbNullString, SW_SHOWNORMAL I want google....
我需要通过一个文本档案,并检查每条线路的开端是否始于“阿蒂鲁特”。 我如何在VB6中这样做?
Dim fso As New FileSystemObject
Dim ts As TextStream
Dim str As String
Set ts = fso.OpenTextFile(MyFile)
Do While Not ts.AtEndOfStream
str = ts.ReadLine
If InStr(str, "Attribute") = 1 Then
do stuff
End If
Loop
使用了“Reex”。 您将须在您的参考资料中加入VB的定期表述图书馆。
Dim reg As new Scripting.Regex().
reg.Pattern = "^Attribute"
If reg.Match(line) Then
Do Something
End If
Dim sInput As String, check as Boolean
check = true
Open "myfile" For INPUT As #txtFile
While Not EOF(txtFile)
Input #txtFile, sInput
If Not Mid(sInput,1,9) = "ATTRIBUTE" Then
check = false
End if
sInput = ""
Wend
Close #txtFile
如果最终检查=真实情况,所有线都从“ATTRIBUTE”开始,否则就没有。
你们可以尝试这样的东西(没有测试的代码)——
Dim ParseDate, AllLinesStartWithAttribute, fso, fs
AllLinesStartWithAttribute = False
Set fso = CreateObject("Scripting.FileSystemObject")
Set fs = fso.OpenTextFile("c:yourfile", 1, True)
Do Until fs.AtEndOfStream
If Left(fs.ReadLine, 9) <> "Attribute" Then
AllLinesStartWithAttribute = False
Exit Do
End If
Loop
fs.Close
Set fs = Nothing
守则一旦实施,如果将<代码>AllLinesStartWithAttribute数值定为真实数值,那么你档案中的所有线就从Attribute开始。 请注意,该守则是敏感的。
Win.ShellExecute 0, "open", "C:dirprogram.exe", "arguments", vbNullString, SW_SHOWNORMAL Win.ShellExecute 0, "open", "http://www.google.com", vbNullString, vbNullString, SW_SHOWNORMAL I want google....
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