Question

I have a variable named l and it contains a string of characters for example echo $l output will be a1,a2,a3,a4,a5,a6,a7,a8,b1,b2,b3

如何寻找b1并把它储存在新的临时中,用于进行情况检查。我不得不 use,因为立场会改变一切。

因此,我的理论将像这样,从这种扼杀中获取1倍,并且将储存在可变的J中。

(千美元)

[j = b1]

之后

 echo "This is a true statment by b1"

else

     echo "This is a false statement not by b1"

fi

这样做的步伐是否比较快,因为我们认为,这些措施是重复的。

增编

Answer 1

我认为,这可能有助于你:

l="a1,a2,a3,a4,a5,a6,a7,a8,b1,b2,b3"
j="b1"
if [[ $l =~ $j ]]; then
    echo "This is a true statement by $j"
else
    echo "This is a false statement by $j"
fi

或

[[ $l =~ $j ]] && echo "This is a true by $j" || echo "This is false by $j"

友情链接