I am having a hard time understanding Floyd-Warshall algorithm. I know how it works as in I know how to do it by hand but I need to understand it through a computer perceptive.
FOR k <-- 1 TO N DO
FOR i <-- 1 TO N DO
FOR j <-- TO N DO
IF Djk + Dkj < DiJ THEN
Dij <-- djk + dkj
k, i and j are variables for iteration and and it iterates till n value, and I guess
it s a nested loop and then it looks at each node less then it finds shortest path?
在Floyd-Warshall,一刀切的含义是图表中的“关点”。 最后两行可作如下解释: “如果你能够从一到千小时,然后从一到三到三分之四走得比从一到三到三分之十快,那么,从一到一到一到三到三条的道路就成为一条最短的道路”。
K代表中间垂直。 因此,外部通道基本上说,让Kth vertex成为中间站。 如果使用K(将K用作中间垂直)的距离低于从垂直到 j(在紧急矩阵中,位置为j)的距离,则内分两端检查每个项目。 如果距离较小,则更新。
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