Question

I was optimizing my app and wanted to know that how much is the size of the object, so that I can also show it in log.

附录一

NSDictionary *temp=(NSDictionary*)[Data objectAtIndex:i];

//data is defined in the .h file

现在我会知道,物体的大小是多少?

我尝试采用不同的观点,在节节中,我发现:

instance_size=(long int)30498656

Is the instance_size the exact size of my temp object?.

我也曾尝试过审判。

sizeof(temp);

但它在这一点上坠毁。任何帮助......

Answer 1

汇编者只了解点人,因此总是会回到点人的规模。寻找被分配物体的大小,就象

NSLog(@"size of Object: %zd", malloc_size(myObject));

Answer 2

首先,我认为,从上述员额中可以清楚地看出,物体大小是按勒科斯的建议和在

The malloc_size(ptr) function returns the size of the memory block that backs the allocation pointed to by ptr. The memory block size is always at least as large as the allocation it backs, and may be larger.

但是,如果你有兴趣确定字典的大小,则要牢记以下几点:

字典储存着关键价值乳制品,在价值部分不包含物体本身,而只是增加“附加”的物体的保留量,并自行提及该物体。现在,词典本身只是提及各种物体(附后钥匙)。因此,如果你在寻找字典提及的所有物体的物体大小,技术上不会是字典的大小。字典的大小是所有钥匙的大小,加上所有与钥匙的参照值的大小,加上母体的大小。如果你仍然有兴趣了解所述物体的大小,试图绕过dict价值阵列:

NSArray *myArray = [myDictionary allValues];
id obj = nil;
int totalSize = 0;
for(obj in myArray)
{
    totalSize += malloc_size(obj);
}
//totalSize now contains the total object size of the refered objects in the dictionary.

Reference

Answer 3

我建议使用<条码>格_getInstanceSize和<条码>小型_good_size,以了解其间隔时间。这不会显示原封不动,也不会出现在返回的面积之内。

#import <malloc/malloc.h>
#import <objc/runtime.h>

NSLog(@"Object Size: %zd", malloc_good_size(class_getInstanceSize([yourObject class])));

Answer 4

Variable temp is a memory address. We can not get the object memory size by programming. We can use the Allocations instrument to optimize app in xcode. Click Command+I in xcode4, you can find it.

Answer 5

In objective- C:

NSString *sampleString = @"iOS Programming";
 NSLog(@"size of object: %zd", malloc_size((__bridge const void *)(sampleString)));

You need to include:
#import<malloc/malloc.h>

In Swift:

var name: String = "Hello World!"

sizeofValue(name)

var someValue: Double = 10.5

sizeofValue(someValue)

In objective- C:

In Swift:

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