Question

我在我的银灯网站点击一个 but子时,我希望我的内容框架能够浏览一个不同页(大约xaml)。我采用以下守则这样做。

ContentFrame.Navigate(new Uri("/Views/About.xaml", UriKind.Relative));

And my ContentFrame looks like this

    <navigation:Frame x:Name="ContentFrame" Style="{StaticResource ContentFrameStyle}" Grid.Row="0" Grid.Column="1" Source="/Home" Navigated="ContentFrame_Navigated" NavigationFailed="ContentFrame_NavigationFailed">
        <navigation:Frame.UriMapper>
            <uriMapper:UriMapper>
                <uriMapper:UriMapping Uri="" MappedUri="/Views/Home.xaml"/>
                <uriMapper:UriMapping Uri="/{pageName}" MappedUri="/Views/{pageName}.xaml"/>
            </uriMapper:UriMapper>
        </navigation:Frame.UriMapper>
    </navigation:Frame>

然而,当我发布消息时,我收到错误信息:

Page not found: "/Views/About"

我的项目希望:

“navigation”/

Answer 1

为此:

ContentFrame.Navigate(new Uri("/About", UriKind.Relative));

Uri地图绘制者应当为你增加道路和扩大。

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