Question

我正试图拿出适当的一致数字,看上去:

  12345
   2345

但我显然不理解yn。我一直在努力遵循these Directive ,并随次尝试进行(它正在编造如此之类,我希望有7和0 decimals):

public class test {

    public static void main( String[] args ) {
        System.out.format("%7.0d%n", 12345);
        System.out.format("%7.0d%n",  2345);
    }
}

但是,我似乎在结尾处是<代码>。非法产品/编码。是否有办法使用这一工具? 如果没有,你会怎样做?

Answer 1

你们可以这样做:

public class Test {
    public static void main( String[] args ) {
        System.out.format("%7d%n", 12345);
        System.out.format("%7d%n",  2345);
    }
}

基本上,该法典要求 Java把地块铺设,使产出具有7个特性。

Answer 2

希望:

public class test {

    public static void main( String[] args ) {
        System.out.format("%7d%n", 12345);
        System.out.format("%7d%n",  2345);
    }
}

Answer 3

从链接页可以看出:

Systemout.format ("%,8d%n”, n); /-> “ 461,012”

你可以 o com,将8岁改为7岁

Answer 4

converter %d is for integers and %f is for float. "%7.0d%n" is used with a float(i.e., as %7.0f%n) and "%7d%n" is used for integer representation.this is the reason for IllegalFormatPrecisionException exception.

参考链接。

友情链接