Question

我需要使用UNIX指挥线的文字,从一起整理的档案中抽取11条随机线。例

Random source file:

1
2
3
4
5
6
7
8
9
10
11
############
12
13
14
15
16
17
18
19
20
21
22

页: 1 请让我:

或

Answer 1

tail -n +$(($RANDOM % 
     ($(wc -l "$filename" | cut -d    -f1) - 11))) "$filename" |
     head -n 11

Tested

页: 1

export filename=/etc/dictionaries-common/words
set -o xtrace

第一次

~$ tail -n +$(($RANDOM % ($(wc -l "$filename" | cut -d    -f1) - 11))) "$filename" | head -n 11
+ head -n 11
++ wc -l /etc/dictionaries-common/words
++ cut  -d   -f1
+ tail -n +11614 /etc/dictionaries-common/words
Moriarty s
Morin
Morin s
Morison
Morison s
Morita
Morita s
Morley
Morley s
Mormon
Mormon s

第二次

~$ tail -n +$(($RANDOM % ($(wc -l "$filename" | cut -d    -f1) - 11))) "$filename" | head -n 11
+ head -n 11
++ wc -l /etc/dictionaries-common/words
++ cut  -d   -f1
+ tail -n +1661 /etc/dictionaries-common/words
Beatrice
Beatrice s
Beatrix
Beatrix s
Beatriz
Beatriz s
Beau
Beau s
Beaufort
Beaufort s
Beaujolais

Answer 2

你可以尝试:

n=$((`wc -l "${file}" | cut -d    -f1` / 11))
m=$(($RANDOM % $n))
tail -n +$(($m * 11)) "${file}" | head -n 11

Tested

友情链接