Question

我知道,在联合材料中,可以分为多条线,但基质是什么?

$( #map ).gameMap({map:[[{"tile":"grass_0","object":""},{"tile":"grass_0","object":""},{"tile":"grass_3","object":""}],[{"tile":"grass_0","object":""},{"tile":"grass_3","object":""},{"tile":"grass_0","object":""}],[{"tile":"grass_1","object":""},{"tile":"grass_0","object":""},{"tile":"grass_2","object":""}]],xpos:-1,ypos:-1,mapsize:3});

我的主管们希望看到一个单页的守则,而无需浏览长线。

Answer 1

当然,...... 然而,只要你在扼杀中不停,你也可以打破僵局。

$( #map ).gameMap(
      {map:[
         [
           {"tile":"grass_0","object":""},
           {"tile":"grass_0","object":""},
           {"tile":"grass_3","object":""}
         ],
         [
           {"tile":"grass_0","object":""},
           {"tile":"grass_3","object":""},
           {"tile":"grass_0","object":""}
         ],
         [
           {"tile":"grass_1","object":""},
           {"tile":"grass_0","object":""},
           {"tile":"grass_2","object":""}
         ]
     ],
     xpos:-1,
     ypos:-1,
     mapsize:3
     }
);

Answer 2

Java本没有矩阵数据结构。这里的物体是字面({map:......>}),其中包含一系列物体字面。

除此之外,正如其他人指出的那样,你当然可以打破多条界线,这还使你有机会增加一些令人敏感的诱惑,使今后能够读写和修改。个人方面:I m a fan of comma-first风格 ,我认为,与同化分界(:)以及健康的白空间相比,这种错误(即:失踪 com)的可读性和可能性最小:

$( #map ).gameMap(
  { map     : [ [ { "tile" : "grass_0", "object" : "" }
                , { "tile" : "grass_0", "object" : "" }
                , { "tile" : "grass_3", "object" : "" }
                ]
              , [ { "tile" : "grass_0", "object" : "" }
                , { "tile" : "grass_3", "object" : "" }
                , { "tile" : "grass_0", "object" : "" }
                ]
              , [ /* and so on... */
                ]
              ]
  , xpos    : -1
  , ypos    : -1
  , mapsize :  3
  }
);

Answer 3

也许像这样:

$( #map ).gameMap({map:[[{"tile":"grass_0","object":""},
                         {"tile":"grass_0","object":""},
                         {"tile":"grass_3","object":""}],
                        [{"tile":"grass_0","object":""},
                         {"tile":"grass_3","object":""},
                         {"tile":"grass_0","object":""}],
                        [{"tile":"grass_1","object":""},
                         {"tile":"grass_0","object":""},
                         {"tile":"grass_2","object":""}]],
                   xpos:-1,
                   ypos:-1,
                   mapsize:3});

Answer 4

您可使用 jsfiddle至tidy Java成文法。这里的产出是:

$( #map ).gameMap({
    map: [[{
        "tile": "grass_0",
        "object": ""},
    {
        "tile": "grass_0",
        "object": ""},
    {
        "tile": "grass_3",
        "object": ""}], [{
        "tile": "grass_0",
        "object": ""},
    {
        "tile": "grass_3",
        "object": ""},
    {
        "tile": "grass_0",
        "object": ""}], [{
        "tile": "grass_1",
        "object": ""},
    {
        "tile": "grass_0",
        "object": ""},
    {
        "tile": "grass_2",
        "object": ""}]],
    xpos: -1,
    ypos: -1,
    mapsize: 3
});

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