Question

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Closed 11 years ago.

如果有一个称为<代码>file.php的文件,则希望其中显示3种内容。页: 1 php?c=1file?php?c=2

我怎么能够这样做?

Example

<html>
<head>
   ...........

<body>

something goes here 1 <show only if "link.com/file.php?c=1 or file.php"

something goes here 2 <show only if "link.com/file.php?c=2

something goes here 3 <show only if "link.com/file.php?c=3    



</body>
</html>

Answer 1

Try this:

if( !isset($_GET[  c  ] ) ){
    # perform file.php actions
} else if( $_GET[  c  ] == 1 ) {
    # perform file.php?c=1 actions
} else if( $_GET[  c  ] == 2 ) {
    # perform file.php?c=2 actions
}

如果有<条码>,则首先进行情况检查。如果有的话,你就掌握了档案。 php经常行动。第二和第三段将让你知道,如果价值为1或2,你会采取什么行动。

如果没有<代码>!

Notice:  Undefined index: c

Answer 2

// $c defaults to 1, if &c=xxx is specified, $c will be intval($_GET[ c ])    
$c = isset($_GET[ c ]) ? intval($_GET[ c ]) : 1;

if ($c == 1) {
    require( f1.php );
} else if ($c == 2) {
    require( f2.php );
} ...

Answer 3

if(!isset($_REQUEST[ c ])){
    require_once(file.php);
}
else if(isset($_REQUEST[ c ])==1){
   require_once(file1.php);
}
else if(isset($_REQUEST[ c ])==2){
   require_once(file2.php);
}

页: 1

友情链接