Question

i am not much familiar with regex expressions use in Java. If i have a String this/is/a/file!/path

now with substring and indexOf i can find the name file appearing inbetween / and ! but i am pretty sure such tasks must be much easier using regexes.

难道有人能给我一个榜样,用雷克语这样做?

Answer 1

另一种办法是使用模式和匹配器。在这方面,你可以使用团体和更为复杂的行动

Pattern pattern = Pattern.compile(yourRegex);
Matcher matcher = pattern.matcher(yourText);
while(matcher.find()) {
   System.out.println(matcher.group(1));
}

检查

Beller :

模式:

Regex in Java : http://docs.oracle.com/javase/tutorial/essential/regex/

Answer 2

∗. 然后,你可以使用配对器找到第1组(母体之间的部分,0组为整个配对)

I didn t test this solution...

Answer 3

You can create a Pattern Object with a regular expression and then create a matcher object from it to parse your String.

String regex = ".*/(.*)!";

Pattern p = Pattern.compile (regex);

Matcher m = p.matcher(StringToBeMatched);

if (m.find()) {

    String filename = m.group (1);
}

Answer 4

Java最简单的使用方式是使用<代码>。 String.matches 方法:

boolean matches = "abc".matches("[a-z]+");

这将产生<代码>true。

这样做的第二种方式是,如果你不得不使用一种特殊的规管模式,则是有益的。您可以汇编并重新使用:

Pattern pattern = Pattern.compile("[a-z]+");
Matcher matcher = pattern.matcher("abc");
boolean matches = matcher.matches();

友情链接