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铁路——如果另一个领域具有一定价值,如何验证一个领域?
原标题:Rails - How to validate a field only if a another field has a certain value?

我以我的形式进行了三重选择:Apple,Banana。 如果我从选定的我中选择<>Apple,把另一个选择领域和一个文本领域与一些 Java稿相连接,因为当选择<>Apple时,就不再需要再填补这两个领域。

So now I have a problem with validating my form when it s submitted. I ve found some similar problems for example in the case of "Only validate a field if another is blank."

这个问题已经解决了:

validates_presence_of :mobile_number, :unless => :home_phone?

因此,我刚刚尝试了我头脑中首件事:

validates_presence_of :state, :granted_at, :if => :type != 1

但是,在我执政时,我发现这一错误:

undefined method `validate  for true:TrueClass

我如何能够根据另一个领域是否具有特别价值而有条件地进行实地验证?

最佳回答

由于这部法律是可执行的法典,因此,你需要将它列入一个或一个像这样的物体:

validates_presence_of :state, :granted_at, :if => lambda { |o| o.type != 1 }

# alternatively:
..., :if => lambda { self.type != 1 }
..., :if => Proc.new { |o| o.type != 1 }
..., :if ->(o) { o.type != 1 }
问题回答

您可使用<条码>。

validates_presence_of :state, :granted_at, :if => lambda {self.type != 1}

或者仅仅制造私人方法:

validates_presence_of :state, :granted_at, :if => :valid_type?

private
def valid_type?
  type != 1
end

尽管上述方式是最佳做法,但你也可以这样简单:

validates_presence_of :state, :granted_at, :if => "type!=1"

Building on the previous answers, you can also use a shorter "arrow" syntax

validates :state, :granted_at, presence: true, if: ->(o) { o.type != 1 }




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