介绍这一类,我用NSScanner &NSCharacterSet写道:

@interface NSString(Splitting)

-(NSArray *) arrayBySeparatingComponentsInCharacterSet:(NSCharacterSet *) charSet;

@end

@implementation NSString(Splitting)

BOOL scanOneCharacterFromSetIntoString(NSScanner *self, NSCharacterSet * charSet, NSString **outStr);
BOOL scanOneCharacterFromSetIntoString(NSScanner *self, NSCharacterSet * charSet, NSString **outStr)
{
    // check for index out of bounds
    NSString *inStr = self.string;

    if (self.scanLocation >= inStr.length)
    {
        return NO;
    }

    unichar ch = [inStr characterAtIndex:self.scanLocation];

    if (![charSet characterIsMember:ch])
    {
        return NO;
    }

    self.scanLocation++;
    if (outStr)
    {
        *outStr = [NSString stringWithCharacters:&ch length:1];
    }

    return YES;
}

-(NSArray *) arrayBySeparatingComponentsInCharacterSet:(NSCharacterSet *)charSet
{
    NSScanner *scanner = [NSScanner scannerWithString:self];
    NSMutableArray *result = [NSMutableArray array];

    NSString *temp = nil;
    while ([scanner scanUpToCharactersFromSet:charSet intoString:&temp] || scanOneCharacterFromSetIntoString(scanner, charSet, &temp)) {;
        [result addObject:temp];

        if ([scanner scanLocation] >= [self length])
        {
            break;
        }

        unichar temp2 = [self characterAtIndex:[scanner scanLocation]];

        if ([charSet characterIsMember:temp2])
        {
            [result addObject:[NSString stringWithFormat:@"%c", temp2]];
            // only update the scan location if the scan was sucessful
            [scanner setScanLocation:[scanner scanLocation] + 1];
        }
    }

    return result;
}

@end

int main (int argc, const char * argv[])
{
    @autoreleasepool {

        NSString *str = @"The 3 quick:"brown fox, jump s" over.";
        NSArray *array = [str arrayBySeparatingComponentsInCharacterSet:[NSCharacterSet characterSetWithCharactersInString:@" :", ."]];
        NSLog(@"%@", array);
    }
}

你们应该做些什么,把《特征集》改变到你们需要的东西。 还指出,与评价中心一起汇编了这一数据,因此,它可能或可能无法在计算参照的环境下妥善管理记忆。