Question

Say I have the following code:

<p>
    Hello
</p>

我也想这样做。

<p>Hello</p>

我要将 cur子置于第1行末的正常状态下,因此,它有权删除所有空间直至其次年。我认为最接近的是这一动议。

d/Hello

删除一切,直至然而,问题在于它也删除了 cur(the > )的特性,因此,我最后要删除。

<pHello
</p>

你们怎样做?

Answer 1

当你赢得胜利时,需要多次重复这一行动。

JxJx

解释:

J           # Join current line with next one but substitute end of line with a space.
x           # Remove the space.
Jx          # Repeat same process for last line.

Answer 2

There s a tag text-object in vim:

put cursor within tag, press vat to select entire tag
press :, it becomes : <, >
type j, it becomes : <, >j
press Enter to join lines

:help v_at

at          "a tag block", select [count] tag blocks, from the
            [count] th unmatched "<aaa>" backwards to the matching
            "</aaa>", including the "<aaa>" and "</aaa>".
            See |tag-blocks| about the details.
            When used in Visual mode it is made characterwise.

Answer 3

当站在第二行的任何地方时(如Hello),则需使用下列钥匙:^d0vatgJ。简单解释:

^ will go to the first non-whitespace character, H
d0 will delete to the beginning of the line
vat will select the entire tag
gJ will join all the lines without inserting spaces

If you start on the H, you can skip the ^ part.

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