Question

#include <iostream>

class SomeClass
{
 public: int *SomeNumber;

 SomeClass() { SomeNumber = new int; *SomeNumber = 5; }

 ~SomeClass() { delete SomeNumber; }
 int getSomeNumber(void) { return *SomeNumber; }

};

int main()
{

SomeClass A;
std:: cout << A.getSomeNumber() << std::endl; // outputs 5
std:: cout << A.SomeNumber << std::endl; // outputs SomeNumber address

return 0;
}

我如何不使用这种方法获得SomeNumber(SomeNumber)而不是地址? 如果一些Number不是墨水的点子,我可以带A.SomeNumber。

Sorry If I were not clear enough. Thanks in advance.

Answer 1

简单:

*A.SomeNumber

由于<代码>,高于*,因此其行文与代码相同。

*(A.SomeNumber)

Answer 2

你可以这样做:

std:: cout << (*A.SomeNumber) << std::endl;

Answer 3

避免使你们的财产公开!

你们可以使用访客设计模式,而不是像这样的守则:

class SomeClass
{
 public: int *SomeNumber;

 SomeClass() { SomeNumber = new int; *SomeNumber = 5; }

 void visit( IVisitor* visitor ){ visitor->doSomething(*SomeNumber);}

 ~SomeClass() { delete SomeNumber; }
 int getSomeNumber(void) { return *SomeNumber; }

};

IVisitor is an interface you can implement it and anything you want.

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