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Jquery的Loop, 采用以下方式:
原标题:Loop in Jquery by using eq
  • 时间:2012-01-16 01:11:20
  •  标签:
  • jquery

我愿借机展示链接名称。 载于四版“测试”中。

$("#test a").each(function (index) {
    alert($("#test a:eq(index)").attr("title"));
})

我获得“未界定”的结果。 如果是,

alert($("#test a:eq(0)").attr("title"))

它正常运转。 谁能帮助我? 感谢您的帮助

问题回答

<代码>.each已经在通过<条码>a要素发出,仅提醒标题:

$("#test a").each(function () {
    alert( this.title );
});

页: 1 您必须确定tindex:

$("#test a").each(function(index) {
    alert( $("#test a:eq(" + index + ")").attr("title") );
});

但你并不真的需要。 您可以简单地使用<代码>。

$("#test a").each(function() {
    alert( $(this).attr("title") );
});

为了明确起见,我总是具体说明关键参数和价值参数。 k 是指数计数,是选择目标,如:

$("#test a").each(function(k, v){
    alert($("#test a:eq(" + k + ")").attr("title"));
});

这方面的一个工作实例





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