我有一个独特的情景。 有一个网络应用程序,是一个模拟器,用以检查XML中的数据发送情况,使数据回归xml,并核实Xml中的一些细节。
现在,我发送的xml数据有许多细节。 在这一xml中,我必须插入我在测试中界定的参数。 我无法得到,在发送之前如何将数据作为Xml的参数发送。
......
id= 12345 ><version>1.3.4<</version><accno>1234567890</accno>add<address details</> ..........
现在,在这种xml结构中,我已经实现了以下参数:<代码><accno>1234567890</accno>。 页: 1
现在,我想在xml中将六氯苯作为参数,而不是在xml的硬编码价值。 请建议如何做到这一点。
我要说的是编辑Xml,reg是坏的。
只是回答直接提问使用等子。 例如。
str.gsub(/reg_match/, newstring)
但这更好的办法是使用hpricot。
或者你也可以使用废墟模板。
require erb
require ostruct
data = {:accno => "1234567890"}
variables = OpenStruct.new(data)
template = "<id= 12345 ><version>1.3.4</version><accno><%= accno%></accno>"
res = ERB.new(template).result(variables.instance_eval { binding })
puts res
XML不是常规的,而是无环境的。 使用Nokogiri等适当的教区,而不是reg。 见。 RegEx对开标进行对等,但XVD自封标记除外。
As answer, as requested.
首先确定模式,然后用 g子取而代之。
xml_data.gsub! (pattern, replacement)
http://ruby-doc.org/docs/ProgrammingRuby/html/ref_c_string.html#String.gsub_oh
这样做的快道是用sub子(如Rajkaran所说)。 http://www.germane-software.com/software/rexml/“rel=“nofollow” 或其他一些Xml图书馆。 投资应当与你今后如何使用此类物品有关。
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