Question

我有:

var ahrefLength = $( a ).length;
for (var i = 0; i < ahrefLength; i++) {
    var ahrefUrl = $( a )[i].attr( href );
    if(ahrefUrl !=   ) {
       $( a )[i].text( Unique );
    }
}

How can I fix this so that no duplicates of "href" appear ? At the moment, if 2 href are the same it fixes both ? i.e. I need to ensure that no duplicates

Answer 1

var list = {};
$( a[href] ).text(function(i,text) {
    var href = $(this).attr( href );
    if( !(href in list) )
        return list[href] =  Unique ;
    else
        ; // what do you want to do with the duplicate?
});

To use a for statement:

var list = {};
var a_els = $( a[href] );  // Cache the DOM selection
var len = a_els.length;

for(var i = 0; i < len; i++) {
    var a_i = a_els.eq(i);
    var href = a_i.attr( href );
    if( !(href in list) )
        a_i.text(list[href] =  Unique );
    else
        ; // what do you want to do with the duplicate?
}

Answer 2

You can use an associative array (viz., an object) as a sort of "set" to keep track of what URLs you ve already seen:

var ahrefLength = $( a ).length;
var hrefsToSkip = {   : true };
for (var i = 0; i < ahrefLength; i++) {
    var ahrefUrl = $( a )[i].attr( href );
    if(! hrefsToSkip[ahrefUrl]) {
       $( a )[i].text( Unique );
       hrefsToSkip[ahrefUrl] = true;
    }
}

Answer 3

var hrefIdx = {};
var href = null;
$( a ).each(function(i, e) {
  href = $(this).attr( href );
  if ( href !=    && !hrefIdx[href]) {
    $(this).text( Unique );
    hrefIdx[href] = true;
  }
});

Answer 4

Use jQuery slice:)

Demo:。

从尾去除所有重复

$( "a" ).each( function() {     
     $( "a[href=" + $( this ).attr( "href" ) + "]" ).slice( 0, -1 ).remove()
 });

将所有重复从第一支柱开始

 $( "a" ).each( function() {     
     var arr = $( "a[href=" + $( this ).attr( "href" ) + "]" );
     arr.slice( 1, arr.length  ).remove()
 });

友情链接