你们如何将以下办法纳入实地选择?
CASE WHEN User.id = $user_id
THEN 0
ELSE 1 END as user_sort
我试图将这一点放在田地内,但结果似乎并未出现。
难道我们能将这一点放在实地阵列中,这样我就能够用我的用户——坦率的话说呢?
http://cakephp.1045679.n5.nabble.com/How-to-use-MySql-s-CASE-WHEN-Function-with-CakePhp-td1259636.html”rel=“noreferer”>,。
$this->Something->find( all , array(
fields => array(
Something.id ,
((CASE WHEN Something.id%2=0 THEN even ELSE odd END)) AS parity
)
));
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