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Closed 11 years ago.

public class CustomBlockFactory
{
private static final Logger logger = 
Logger.getLogger(TableListControllerFactory.class.getName());

public static AndroidTourController getController(TourControllerParameters 
paramTourControllerParameters, TourSequencer paramTourSequencer)
{
((CustomBlock)paramTourControllerParameters);
return new EnableTableController(paramTourControllerParameters, paramTourSequencer);
}
}

I m 在(CustomBlock)paramTourControllerParailes上出现错误;因为“任务左侧必须是变数”。

是否有任何人可以纠正这一错误?

预收

Answer 1

它想像你试图将参数<代码>参数<>。因此,你可以打电话到<代码>可调制的Controller。然而,由于投放经营人not<>/em>改变了变量的静态类型,你的代码赢得了t工作。

相反,你可以产生一种新变量,即预期类型,并将投放者的结果分配给这一变量:

public static AndroidTourController getController( TourControllerParameters paramTourControllerParameters, TourSequencer paramTourSequencer) { CustomBlock customBlock = (CustomBlock)paramTourControllerParameters; return new EnableTableController(customBlock, paramTourSequencer); }

或者,你可以忽略临时变数,在一份声明中写出投稿和造价单:

return new EnableTableController( (CustomBlock)paramTourControllerParameters, paramTourSequencer);

Answer 2

Because you re doing nothing with this code

((CustomBlock)paramTourControllerParameters);

你们是否希望这样做?

return new EnableTableController((CustomBlock) paramTourControllerParameters, paramTourSequencer);

Answer 3

((CustomBlock)paramTourControllerParameters); will cast paramTourControllerParameters into CustomBlock , so you need to store it into new variable like

CustomClock customClock = ((CustomBlock)paramTourControllerParameters);

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