一. 简单案情陈述
CASE WHEN @SPOID is not null THEN
(176)
ELSE
(SELECT designationID from setupdesignations where reportto = 99)
END
When else clause of this statement execute it gives me the following error
Subquery returned more than 1 value. This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the subquery is used as an expression.
我在<代码>中使用这一发言。 缩略语 我预计,在其他情况下,会有多重结果,但给我上述错误。 如果我删除案件陈述,在询问中执行其他部分,则取得预期结果。
您不能在化学文摘社国际协会的配对处使用一种子电作为表达方式,它期望有单一价值。 而是如何处理;
where
(@SPOID is not null and infield = 176)
or
(@SPOID is null and infield in (SELECT designationID from setupdesignations where reportto = 99))
虽然您使用<代码>IN。 条款,CASE的声明只允许一行作为返回声明。
你们必须拿出另一种方式。
修改条款如下:
... in
(SELECT designationID
from setupdesignations
where reportto = 99 and @SPOID is not null
UNION
SELECT 176 where @SPOID is null)
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