Question

i want to create an object dynamically of the form - {"abc": [x1,x2], "efg": [x3, x4, x1]} The following code is not working.. what s the problem here ?

var catCmp = {};
var x1="abc";
var x2="efg";

var y1="x1";
var y2="x2";
var y3="x3";
var y4="x4";

if (typeof catCmp[x1] ===  undefined ) {
    catCmp[x1] = [];
}
if (typeof catCmp[x2] ===  undefined ) {
    catCmp[x2] = [];
}

catCmp[x1] = catCmp[x1].push(y1);
catCmp[x1] = catCmp[x1].push(y2);
catCmp[x2] = catCmp[x2].push(y3);
catCmp[x2] = catCmp[x2].push(y4);
catCmp[x2] = catCmp[x2].push(y1);

console.log( catCmp ::: , catCmp);

Answer 1

你们不需要放弃推动行动的结果。页: 1

Answer 2

如下:

catCmp[x1] = catCmp[x1].push(y1);

由<代码>catCmp[x1]push(y1)退还的价值为y1。因此,这是分配给<代码>catCmp[x1]的价值。

正如其他答复中所建议的那样,没有做转让,只是:

catCmp[x1].push(y1);

Answer 3

catCmp[x1].push(y1);
catCmp[x1].push(y2);
catCmp[x2].push(y3);
catCmp[x2].push(y4);
catCmp[x2].push(y1);

Answer 4

Java曲推法回收了新长的推进方法。

So, in your case, the statement

catCmp[x1] = catCmp[x1].push(y1);

c)Cmp[x1] = catCmp[x1]。

Not just you need not, you should not assign back the result of push operation. So, just use:

catCmp[x1].push(y1);

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